4(t^2-1)(t+2)=0

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Solution for 4(t^2-1)(t+2)=0 equation: 


Simplifying
4(t2 + -1)(t + 2) = 0

Reorder the terms:
4(-1 + t2)(t + 2) = 0

Reorder the terms:
4(-1 + t2)(2 + t) = 0

Multiply (-1 + t2) * (2 + t)
4(-1(2 + t) + t2(2 + t)) = 0
4((2 * -1 + t * -1) + t2(2 + t)) = 0
4((-2 + -1t) + t2(2 + t)) = 0
4(-2 + -1t + (2 * t2 + t * t2)) = 0
4(-2 + -1t + (2t2 + t3)) = 0
4(-2 + -1t + 2t2 + t3) = 0
(-2 * 4 + -1t * 4 + 2t2 * 4 + t3 * 4) = 0
(-8 + -4t + 8t2 + 4t3) = 0

Solving
-8 + -4t + 8t2 + 4t3 = 0

Solving for variable 't'.

Factor out the Greatest Common Factor (GCF), '4'.
4(-2 + -1t + 2t2 + t3) = 0

Ignore the factor 4.

Subproblem 1
Set the factor '(-2 + -1t + 2t2 + t3)' equal to zero and attempt to solve:

Simplifying
-2 + -1t + 2t2 + t3 = 0

Solving
-2 + -1t + 2t2 + t3 = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

The solution to this equation could not be determined.

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